F(x)=3x^2-8x

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Solution for F(x)=3x^2-8x equation:



(F)=3F^2-8F
We move all terms to the left:
(F)-(3F^2-8F)=0
We get rid of parentheses
-3F^2+F+8F=0
We add all the numbers together, and all the variables
-3F^2+9F=0
a = -3; b = 9; c = 0;
Δ = b2-4ac
Δ = 92-4·(-3)·0
Δ = 81
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$F_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$F_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{81}=9$
$F_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(9)-9}{2*-3}=\frac{-18}{-6} =+3 $
$F_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(9)+9}{2*-3}=\frac{0}{-6} =0 $

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